3(3-b)-33=27b-6(4+5b)

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Solution for 3(3-b)-33=27b-6(4+5b) equation: 



3(3-b)-33=27b-6(4+5b)

We move all terms to the left:

3(3-b)-33-(27b-6(4+5b))=0

We add all the numbers together, and all the variables

3(-1b+3)-(27b-6(5b+4))-33=0

We multiply parentheses

-3b-(27b-6(5b+4))+9-33=0



We calculate terms in parentheses: -(27b-6(5b+4)), so:

27b-6(5b+4)

We multiply parentheses

27b-30b-24

We add all the numbers together, and all the variables

-3b-24

Back to the equation:

-(-3b-24)



We add all the numbers together, and all the variables

-3b-(-3b-24)-24=0

We get rid of parentheses

-3b+3b+24-24=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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