3(3-f)=5(f-10)+3

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Solution for 3(3-f)=5(f-10)+3 equation: 



3(3-f)=5(f-10)+3

We move all terms to the left:

3(3-f)-(5(f-10)+3)=0

We add all the numbers together, and all the variables

3(-1f+3)-(5(f-10)+3)=0

We multiply parentheses

-3f-(5(f-10)+3)+9=0



We calculate terms in parentheses: -(5(f-10)+3), so:

5(f-10)+3

We multiply parentheses

5f-50+3

We add all the numbers together, and all the variables

5f-47

Back to the equation:

-(5f-47)



We get rid of parentheses

-3f-5f+47+9=0

We add all the numbers together, and all the variables

-8f+56=0

We move all terms containing f to the left, all other terms to the right

-8f=-56

f=-56/-8

f=+7

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