3(3-f)=5(f-10+3)

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Solution for 3(3-f)=5(f-10+3) equation: 



3(3-f)=5(f-10+3)

We move all terms to the left:

3(3-f)-(5(f-10+3))=0

We add all the numbers together, and all the variables

3(-1f+3)-(5(f-7))=0

We multiply parentheses

-3f-(5(f-7))+9=0



We calculate terms in parentheses: -(5(f-7)), so:

5(f-7)

We multiply parentheses

5f-35

Back to the equation:

-(5f-35)



We get rid of parentheses

-3f-5f+35+9=0

We add all the numbers together, and all the variables

-8f+44=0

We move all terms containing f to the left, all other terms to the right

-8f=-44

f=-44/-8

f=5+1/2

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