3(3-x)+1=2x+2-3(1-2x)

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Solution for 3(3-x)+1=2x+2-3(1-2x) equation: 



3(3-x)+1=2x+2-3(1-2x)

We move all terms to the left:

3(3-x)+1-(2x+2-3(1-2x))=0

We add all the numbers together, and all the variables

3(-1x+3)-(2x+2-3(-2x+1))+1=0

We multiply parentheses

-3x-(2x+2-3(-2x+1))+9+1=0



We calculate terms in parentheses: -(2x+2-3(-2x+1)), so:

2x+2-3(-2x+1)

determiningTheFunctionDomain
2x-3(-2x+1)+2

We multiply parentheses

2x+6x-3+2

We add all the numbers together, and all the variables

8x-1

Back to the equation:

-(8x-1)



We add all the numbers together, and all the variables

-3x-(8x-1)+10=0

We get rid of parentheses

-3x-8x+1+10=0

We add all the numbers together, and all the variables

-11x+11=0

We move all terms containing x to the left, all other terms to the right

-11x=-11

x=-11/-11

x=1

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