3(3-x)+9=2(x-4)+7

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Solution for 3(3-x)+9=2(x-4)+7 equation: 



3(3-x)+9=2(x-4)+7

We move all terms to the left:

3(3-x)+9-(2(x-4)+7)=0

We add all the numbers together, and all the variables

3(-1x+3)-(2(x-4)+7)+9=0

We multiply parentheses

-3x-(2(x-4)+7)+9+9=0



We calculate terms in parentheses: -(2(x-4)+7), so:

2(x-4)+7

We multiply parentheses

2x-8+7

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

-3x-(2x-1)+18=0

We get rid of parentheses

-3x-2x+1+18=0

We add all the numbers together, and all the variables

-5x+19=0

We move all terms containing x to the left, all other terms to the right

-5x=-19

x=-19/-5

x=3+4/5

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