3(3-x)+sx=2(x+2)

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Solution for 3(3-x)+sx=2(x+2) equation: 


Simplifying
3(3 + -1x) + sx = 2(x + 2)
(3 * 3 + -1x * 3) + sx = 2(x + 2)
(9 + -3x) + sx = 2(x + 2)

Reorder the terms:
9 + sx + -3x = 2(x + 2)

Reorder the terms:
9 + sx + -3x = 2(2 + x)
9 + sx + -3x = (2 * 2 + x * 2)
9 + sx + -3x = (4 + 2x)

Solving
9 + sx + -3x = 4 + 2x

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + sx + -9 + -3x = 4 + -9 + 2x

Reorder the terms:
9 + -9 + sx + -3x = 4 + -9 + 2x

Combine like terms: 9 + -9 = 0
0 + sx + -3x = 4 + -9 + 2x
sx + -3x = 4 + -9 + 2x

Combine like terms: 4 + -9 = -5
sx + -3x = -5 + 2x

Add '3x' to each side of the equation.
sx + -3x + 3x = -5 + 2x + 3x

Combine like terms: -3x + 3x = 0
sx + 0 = -5 + 2x + 3x
sx = -5 + 2x + 3x

Combine like terms: 2x + 3x = 5x
sx = -5 + 5x

Divide each side by 'x'.
s = -5x-1 + 5

Simplifying
s = -5x-1 + 5

Reorder the terms:
s = 5 + -5x-1

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