3(3-y)-19=17y-5(2+4y)

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Solution for 3(3-y)-19=17y-5(2+4y) equation: 



3(3-y)-19=17y-5(2+4y)

We move all terms to the left:

3(3-y)-19-(17y-5(2+4y))=0

We add all the numbers together, and all the variables

3(-1y+3)-(17y-5(4y+2))-19=0

We multiply parentheses

-3y-(17y-5(4y+2))+9-19=0



We calculate terms in parentheses: -(17y-5(4y+2)), so:

17y-5(4y+2)

We multiply parentheses

17y-20y-10

We add all the numbers together, and all the variables

-3y-10

Back to the equation:

-(-3y-10)



We add all the numbers together, and all the variables

-3y-(-3y-10)-10=0

We get rid of parentheses

-3y+3y+10-10=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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