3(3-z)-17=17z-4(2+5z)

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Solution for 3(3-z)-17=17z-4(2+5z) equation: 



3(3-z)-17=17z-4(2+5z)

We move all terms to the left:

3(3-z)-17-(17z-4(2+5z))=0

We add all the numbers together, and all the variables

3(-1z+3)-(17z-4(5z+2))-17=0

We multiply parentheses

-3z-(17z-4(5z+2))+9-17=0



We calculate terms in parentheses: -(17z-4(5z+2)), so:

17z-4(5z+2)

We multiply parentheses

17z-20z-8

We add all the numbers together, and all the variables

-3z-8

Back to the equation:

-(-3z-8)



We add all the numbers together, and all the variables

-3z-(-3z-8)-8=0

We get rid of parentheses

-3z+3z+8-8=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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