3(3-z)-19=17z-5(2+4z)

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Solution for 3(3-z)-19=17z-5(2+4z) equation: 


Simplifying
3(3 + -1z) + -19 = 17z + -5(2 + 4z)
(3 * 3 + -1z * 3) + -19 = 17z + -5(2 + 4z)
(9 + -3z) + -19 = 17z + -5(2 + 4z)

Reorder the terms:
9 + -19 + -3z = 17z + -5(2 + 4z)

Combine like terms: 9 + -19 = -10
-10 + -3z = 17z + -5(2 + 4z)
-10 + -3z = 17z + (2 * -5 + 4z * -5)
-10 + -3z = 17z + (-10 + -20z)

Reorder the terms:
-10 + -3z = -10 + 17z + -20z

Combine like terms: 17z + -20z = -3z
-10 + -3z = -10 + -3z

Add '10' to each side of the equation.
-10 + 10 + -3z = -10 + 10 + -3z

Combine like terms: -10 + 10 = 0
0 + -3z = -10 + 10 + -3z
-3z = -10 + 10 + -3z

Combine like terms: -10 + 10 = 0
-3z = 0 + -3z
-3z = -3z

Add '3z' to each side of the equation.
-3z + 3z = -3z + 3z

Combine like terms: -3z + 3z = 0
0 = -3z + 3z

Combine like terms: -3z + 3z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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