3(34-2y)+7y=103

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Solution for 3(34-2y)+7y=103 equation: 



3(34-2y)+7y=103

We move all terms to the left:

3(34-2y)+7y-(103)=0

We add all the numbers together, and all the variables

3(-2y+34)+7y-103=0

We add all the numbers together, and all the variables

7y+3(-2y+34)-103=0

We multiply parentheses

7y-6y+102-103=0

We add all the numbers together, and all the variables

y-1=0

We move all terms containing y to the left, all other terms to the right

y=1

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