3(3a-4)-4a=8-5(a-8)

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Solution for 3(3a-4)-4a=8-5(a-8) equation: 



3(3a-4)-4a=8-5(a-8)

We move all terms to the left:

3(3a-4)-4a-(8-5(a-8))=0

We add all the numbers together, and all the variables

-4a+3(3a-4)-(8-5(a-8))=0

We multiply parentheses

-4a+9a-(8-5(a-8))-12=0



We calculate terms in parentheses: -(8-5(a-8)), so:

8-5(a-8)

determiningTheFunctionDomain
-5(a-8)+8

We multiply parentheses

-5a+40+8

We add all the numbers together, and all the variables

-5a+48

Back to the equation:

-(-5a+48)



We add all the numbers together, and all the variables

5a-(-5a+48)-12=0

We get rid of parentheses

5a+5a-48-12=0

We add all the numbers together, and all the variables

10a-60=0

We move all terms containing a to the left, all other terms to the right

10a=60

a=60/10

a=6

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