3(3a-5)=4(10-a)

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Solution for 3(3a-5)=4(10-a) equation: 



3(3a-5)=4(10-a)

We move all terms to the left:

3(3a-5)-(4(10-a))=0

We add all the numbers together, and all the variables

3(3a-5)-(4(-1a+10))=0

We multiply parentheses

9a-(4(-1a+10))-15=0



We calculate terms in parentheses: -(4(-1a+10)), so:

4(-1a+10)

We multiply parentheses

-4a+40

Back to the equation:

-(-4a+40)



We get rid of parentheses

9a+4a-40-15=0

We add all the numbers together, and all the variables

13a-55=0

We move all terms containing a to the left, all other terms to the right

13a=55

a=55/13

a=4+3/13

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