3(3b+1)-(b-1)=6(b+10)

Solution for 3(3b+1)-(b-1)=6(b+10) equation:

3(3b+1)-(b-1)=6(b+10)

We move all terms to the left:

3(3b+1)-(b-1)-(6(b+10))=0

We multiply parentheses

9b-(b-1)-(6(b+10))+3=0

We get rid of parentheses

9b-b-(6(b+10))+1+3=0


We calculate terms in parentheses: -(6(b+10)), so:

6(b+10)

We multiply parentheses

6b+60

Back to the equation:

-(6b+60)


We add all the numbers together, and all the variables

8b-(6b+60)+4=0

We get rid of parentheses

8b-6b-60+4=0

We add all the numbers together, and all the variables

2b-56=0

We move all terms containing b to the left, all other terms to the right

2b=56

b=56/2

b=28