3(3b+12)+3(b+4)=

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Solution for 3(3b+12)+3(b+4)= equation:


Simplifying
3(3b + 12) + 3(b + 4) = 0

Reorder the terms:
3(12 + 3b) + 3(b + 4) = 0
(12 * 3 + 3b * 3) + 3(b + 4) = 0
(36 + 9b) + 3(b + 4) = 0

Reorder the terms:
36 + 9b + 3(4 + b) = 0
36 + 9b + (4 * 3 + b * 3) = 0
36 + 9b + (12 + 3b) = 0

Reorder the terms:
36 + 12 + 9b + 3b = 0

Combine like terms: 36 + 12 = 48
48 + 9b + 3b = 0

Combine like terms: 9b + 3b = 12b
48 + 12b = 0

Solving
48 + 12b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-48' to each side of the equation.
48 + -48 + 12b = 0 + -48

Combine like terms: 48 + -48 = 0
0 + 12b = 0 + -48
12b = 0 + -48

Combine like terms: 0 + -48 = -48
12b = -48

Divide each side by '12'.
b = -4

Simplifying
b = -4

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