3(3b+2)+(10b-3)=0

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Solution for 3(3b+2)+(10b-3)=0 equation:


Simplifying
3(3b + 2) + (10b + -3) = 0

Reorder the terms:
3(2 + 3b) + (10b + -3) = 0
(2 * 3 + 3b * 3) + (10b + -3) = 0
(6 + 9b) + (10b + -3) = 0

Reorder the terms:
6 + 9b + (-3 + 10b) = 0

Remove parenthesis around (-3 + 10b)
6 + 9b + -3 + 10b = 0

Reorder the terms:
6 + -3 + 9b + 10b = 0

Combine like terms: 6 + -3 = 3
3 + 9b + 10b = 0

Combine like terms: 9b + 10b = 19b
3 + 19b = 0

Solving
3 + 19b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 19b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 19b = 0 + -3
19b = 0 + -3

Combine like terms: 0 + -3 = -3
19b = -3

Divide each side by '19'.
b = -0.1578947368

Simplifying
b = -0.1578947368

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