3(3b+3)=2b+30

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Solution for 3(3b+3)=2b+30 equation: 



3(3b+3)=2b+30

We move all terms to the left:

3(3b+3)-(2b+30)=0

We multiply parentheses

9b-(2b+30)+9=0

We get rid of parentheses

9b-2b-30+9=0

We add all the numbers together, and all the variables

7b-21=0

We move all terms containing b to the left, all other terms to the right

7b=21

b=21/7

b=3

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