3(3b+4)=2(5b+1)

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Solution for 3(3b+4)=2(5b+1) equation: 



3(3b+4)=2(5b+1)

We move all terms to the left:

3(3b+4)-(2(5b+1))=0

We multiply parentheses

9b-(2(5b+1))+12=0



We calculate terms in parentheses: -(2(5b+1)), so:

2(5b+1)

We multiply parentheses

10b+2

Back to the equation:

-(10b+2)



We get rid of parentheses

9b-10b-2+12=0

We add all the numbers together, and all the variables

-1b+10=0

We move all terms containing b to the left, all other terms to the right

-b=-10

b=-10/-1

b=+10

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