3(3b+4b)=105

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Solution for 3(3b+4b)=105 equation: 



3(3b+4b)=105

We move all terms to the left:

3(3b+4b)-(105)=0

We add all the numbers together, and all the variables

3(+7b)-105=0

We multiply parentheses

21b-105=0

We move all terms containing b to the left, all other terms to the right

21b=105

b=105/21

b=5

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