3(3b-1)=5(b+1)

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Solution for 3(3b-1)=5(b+1) equation: 



3(3b-1)=5(b+1)

We move all terms to the left:

3(3b-1)-(5(b+1))=0

We multiply parentheses

9b-(5(b+1))-3=0



We calculate terms in parentheses: -(5(b+1)), so:

5(b+1)

We multiply parentheses

5b+5

Back to the equation:

-(5b+5)



We get rid of parentheses

9b-5b-5-3=0

We add all the numbers together, and all the variables

4b-8=0

We move all terms containing b to the left, all other terms to the right

4b=8

b=8/4

b=2

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