3(3b-2)=-3b+30

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Solution for 3(3b-2)=-3b+30 equation: 



3(3b-2)=-3b+30

We move all terms to the left:

3(3b-2)-(-3b+30)=0

We multiply parentheses

9b-(-3b+30)-6=0

We get rid of parentheses

9b+3b-30-6=0

We add all the numbers together, and all the variables

12b-36=0

We move all terms containing b to the left, all other terms to the right

12b=36

b=36/12

b=3

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