3(3b-5)=12

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Solution for 3(3b-5)=12 equation: 



3(3b-5)=12

We move all terms to the left:

3(3b-5)-(12)=0

We multiply parentheses

9b-15-12=0

We add all the numbers together, and all the variables

9b-27=0

We move all terms containing b to the left, all other terms to the right

9b=27

b=27/9

b=3

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