3(3b-5)=2(b+3)

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Solution for 3(3b-5)=2(b+3) equation:



3(3b-5)=2(b+3)
We move all terms to the left:
3(3b-5)-(2(b+3))=0
We multiply parentheses
9b-(2(b+3))-15=0
We calculate terms in parentheses: -(2(b+3)), so:
2(b+3)
We multiply parentheses
2b+6
Back to the equation:
-(2b+6)
We get rid of parentheses
9b-2b-6-15=0
We add all the numbers together, and all the variables
7b-21=0
We move all terms containing b to the left, all other terms to the right
7b=21
b=21/7
b=3

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