3(3b-6)+3b=18+6b

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Solution for 3(3b-6)+3b=18+6b equation:



3(3b-6)+3b=18+6b
We move all terms to the left:
3(3b-6)+3b-(18+6b)=0
We add all the numbers together, and all the variables
3(3b-6)+3b-(6b+18)=0
We add all the numbers together, and all the variables
3b+3(3b-6)-(6b+18)=0
We multiply parentheses
3b+9b-(6b+18)-18=0
We get rid of parentheses
3b+9b-6b-18-18=0
We add all the numbers together, and all the variables
6b-36=0
We move all terms containing b to the left, all other terms to the right
6b=36
b=36/6
b=6

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