3(3c+1)3=4c+9

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Solution for 3(3c+1)3=4c+9 equation: 



3(3c+1)3=4c+9

We move all terms to the left:

3(3c+1)3-(4c+9)=0

We multiply parentheses

27c-(4c+9)+9=0

We get rid of parentheses

27c-4c-9+9=0

We add all the numbers together, and all the variables

23c=0

c=0/23

c=0

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