3(3c+10)=57

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Solution for 3(3c+10)=57 equation: 



3(3c+10)=57

We move all terms to the left:

3(3c+10)-(57)=0

We multiply parentheses

9c+30-57=0

We add all the numbers together, and all the variables

9c-27=0

We move all terms containing c to the left, all other terms to the right

9c=27

c=27/9

c=3

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