3(3c+16)=3c+12

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Solution for 3(3c+16)=3c+12 equation: 



3(3c+16)=3c+12

We move all terms to the left:

3(3c+16)-(3c+12)=0

We multiply parentheses

9c-(3c+12)+48=0

We get rid of parentheses

9c-3c-12+48=0

We add all the numbers together, and all the variables

6c+36=0

We move all terms containing c to the left, all other terms to the right

6c=-36

c=-36/6

c=-6

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