3(3c+2)-8(c+1)=7

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Solution for 3(3c+2)-8(c+1)=7 equation:


Simplifying
3(3c + 2) + -8(c + 1) = 7

Reorder the terms:
3(2 + 3c) + -8(c + 1) = 7
(2 * 3 + 3c * 3) + -8(c + 1) = 7
(6 + 9c) + -8(c + 1) = 7

Reorder the terms:
6 + 9c + -8(1 + c) = 7
6 + 9c + (1 * -8 + c * -8) = 7
6 + 9c + (-8 + -8c) = 7

Reorder the terms:
6 + -8 + 9c + -8c = 7

Combine like terms: 6 + -8 = -2
-2 + 9c + -8c = 7

Combine like terms: 9c + -8c = 1c
-2 + 1c = 7

Solving
-2 + 1c = 7

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 1c = 7 + 2

Combine like terms: -2 + 2 = 0
0 + 1c = 7 + 2
1c = 7 + 2

Combine like terms: 7 + 2 = 9
1c = 9

Divide each side by '1'.
c = 9

Simplifying
c = 9

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