3(3c+2)=5(2c-1)

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Solution for 3(3c+2)=5(2c-1) equation: 



3(3c+2)=5(2c-1)

We move all terms to the left:

3(3c+2)-(5(2c-1))=0

We multiply parentheses

9c-(5(2c-1))+6=0



We calculate terms in parentheses: -(5(2c-1)), so:

5(2c-1)

We multiply parentheses

10c-5

Back to the equation:

-(10c-5)



We get rid of parentheses

9c-10c+5+6=0

We add all the numbers together, and all the variables

-1c+11=0

We move all terms containing c to the left, all other terms to the right

-c=-11

c=-11/-1

c=+11

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