3(3c+4)-13=17+3(2c-4)

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Solution for 3(3c+4)-13=17+3(2c-4) equation: 



3(3c+4)-13=17+3(2c-4)

We move all terms to the left:

3(3c+4)-13-(17+3(2c-4))=0

We multiply parentheses

9c-(17+3(2c-4))+12-13=0



We calculate terms in parentheses: -(17+3(2c-4)), so:

17+3(2c-4)

determiningTheFunctionDomain
3(2c-4)+17

We multiply parentheses

6c-12+17

We add all the numbers together, and all the variables

6c+5

Back to the equation:

-(6c+5)



We add all the numbers together, and all the variables

9c-(6c+5)-1=0

We get rid of parentheses

9c-6c-5-1=0

We add all the numbers together, and all the variables

3c-6=0

We move all terms containing c to the left, all other terms to the right

3c=6

c=6/3

c=2

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