3(3c+4)-3c=2(3c+6)

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Solution for 3(3c+4)-3c=2(3c+6) equation:



3(3c+4)-3c=2(3c+6)
We move all terms to the left:
3(3c+4)-3c-(2(3c+6))=0
We add all the numbers together, and all the variables
-3c+3(3c+4)-(2(3c+6))=0
We multiply parentheses
-3c+9c-(2(3c+6))+12=0
We calculate terms in parentheses: -(2(3c+6)), so:
2(3c+6)
We multiply parentheses
6c+12
Back to the equation:
-(6c+12)
We add all the numbers together, and all the variables
6c-(6c+12)+12=0
We get rid of parentheses
6c-6c-12+12=0
We add all the numbers together, and all the variables
=0
c=0/1
c=0

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