3(3c+4)-3c=2(3c+6)

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Solution for 3(3c+4)-3c=2(3c+6) equation: 



3(3c+4)-3c=2(3c+6)

We move all terms to the left:

3(3c+4)-3c-(2(3c+6))=0

We add all the numbers together, and all the variables

-3c+3(3c+4)-(2(3c+6))=0

We multiply parentheses

-3c+9c-(2(3c+6))+12=0



We calculate terms in parentheses: -(2(3c+6)), so:

2(3c+6)

We multiply parentheses

6c+12

Back to the equation:

-(6c+12)



We add all the numbers together, and all the variables

6c-(6c+12)+12=0

We get rid of parentheses

6c-6c-12+12=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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