3(3c+4)=8(c-2)

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Solution for 3(3c+4)=8(c-2) equation:


Simplifying
3(3c + 4) = 8(c + -2)

Reorder the terms:
3(4 + 3c) = 8(c + -2)
(4 * 3 + 3c * 3) = 8(c + -2)
(12 + 9c) = 8(c + -2)

Reorder the terms:
12 + 9c = 8(-2 + c)
12 + 9c = (-2 * 8 + c * 8)
12 + 9c = (-16 + 8c)

Solving
12 + 9c = -16 + 8c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8c' to each side of the equation.
12 + 9c + -8c = -16 + 8c + -8c

Combine like terms: 9c + -8c = 1c
12 + 1c = -16 + 8c + -8c

Combine like terms: 8c + -8c = 0
12 + 1c = -16 + 0
12 + 1c = -16

Add '-12' to each side of the equation.
12 + -12 + 1c = -16 + -12

Combine like terms: 12 + -12 = 0
0 + 1c = -16 + -12
1c = -16 + -12

Combine like terms: -16 + -12 = -28
1c = -28

Divide each side by '1'.
c = -28

Simplifying
c = -28

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