3(3c-1)-6=6c+6

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Solution for 3(3c-1)-6=6c+6 equation: 



3(3c-1)-6=6c+6

We move all terms to the left:

3(3c-1)-6-(6c+6)=0

We multiply parentheses

9c-(6c+6)-3-6=0

We get rid of parentheses

9c-6c-6-3-6=0

We add all the numbers together, and all the variables

3c-15=0

We move all terms containing c to the left, all other terms to the right

3c=15

c=15/3

c=5

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