3(3c-2)=5(-2c-1)

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Solution for 3(3c-2)=5(-2c-1) equation: 



3(3c-2)=5(-2c-1)

We move all terms to the left:

3(3c-2)-(5(-2c-1))=0

We multiply parentheses

9c-(5(-2c-1))-6=0



We calculate terms in parentheses: -(5(-2c-1)), so:

5(-2c-1)

We multiply parentheses

-10c-5

Back to the equation:

-(-10c-5)



We get rid of parentheses

9c+10c+5-6=0

We add all the numbers together, and all the variables

19c-1=0

We move all terms containing c to the left, all other terms to the right

19c=1

c=1/19

c=1/19

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