3(3c-5)=-(-18c-30)

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Solution for 3(3c-5)=-(-18c-30) equation: 



3(3c-5)=-(-18c-30)

We move all terms to the left:

3(3c-5)-(-(-18c-30))=0

We multiply parentheses

9c-(-(-18c-30))-15=0



We calculate terms in parentheses: -(-(-18c-30)), so:

-(-18c-30)

We get rid of parentheses

18c+30

Back to the equation:

-(18c+30)



We get rid of parentheses

9c-18c-30-15=0

We add all the numbers together, and all the variables

-9c-45=0

We move all terms containing c to the left, all other terms to the right

-9c=45

c=45/-9

c=-5

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