3(3c-5)=21

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Solution for 3(3c-5)=21 equation: 



3(3c-5)=21

We move all terms to the left:

3(3c-5)-(21)=0

We multiply parentheses

9c-15-21=0

We add all the numbers together, and all the variables

9c-36=0

We move all terms containing c to the left, all other terms to the right

9c=36

c=36/9

c=4

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