3(3c-5)=4(c+5)

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Solution for 3(3c-5)=4(c+5) equation:


Simplifying
3(3c + -5) = 4(c + 5)

Reorder the terms:
3(-5 + 3c) = 4(c + 5)
(-5 * 3 + 3c * 3) = 4(c + 5)
(-15 + 9c) = 4(c + 5)

Reorder the terms:
-15 + 9c = 4(5 + c)
-15 + 9c = (5 * 4 + c * 4)
-15 + 9c = (20 + 4c)

Solving
-15 + 9c = 20 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-15 + 9c + -4c = 20 + 4c + -4c

Combine like terms: 9c + -4c = 5c
-15 + 5c = 20 + 4c + -4c

Combine like terms: 4c + -4c = 0
-15 + 5c = 20 + 0
-15 + 5c = 20

Add '15' to each side of the equation.
-15 + 15 + 5c = 20 + 15

Combine like terms: -15 + 15 = 0
0 + 5c = 20 + 15
5c = 20 + 15

Combine like terms: 20 + 15 = 35
5c = 35

Divide each side by '5'.
c = 7

Simplifying
c = 7

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