3(3c=5)+1=2(c-20)

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Solution for 3(3c=5)+1=2(c-20) equation: 



3(3c=5)+1=2(c-20)

We move all terms to the left:

3(3c-(5)+1)=0

We add all the numbers together, and all the variables

3(3c-4)=0

We multiply parentheses

9c-12=0

We move all terms containing c to the left, all other terms to the right

9c=12

c=12/9

c=1+1/3

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