3(3d+4)-(3d-2)=38

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Solution for 3(3d+4)-(3d-2)=38 equation: 



3(3d+4)-(3d-2)=38

We move all terms to the left:

3(3d+4)-(3d-2)-(38)=0

We multiply parentheses

9d-(3d-2)+12-38=0

We get rid of parentheses

9d-3d+2+12-38=0

We add all the numbers together, and all the variables

6d-24=0

We move all terms containing d to the left, all other terms to the right

6d=24

d=24/6

d=4

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