3(3e+7)-7(e+3)=5(e-2)-2(e+1)

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Solution for 3(3e+7)-7(e+3)=5(e-2)-2(e+1) equation: 



3(3e+7)-7(e+3)=5(e-2)-2(e+1)

We move all terms to the left:

3(3e+7)-7(e+3)-(5(e-2)-2(e+1))=0

We multiply parentheses

9e-7e-(5(e-2)-2(e+1))+21-21=0



We calculate terms in parentheses: -(5(e-2)-2(e+1)), so:

5(e-2)-2(e+1)

We multiply parentheses

5e-2e-10-2

We add all the numbers together, and all the variables

3e-12

Back to the equation:

-(3e-12)



We add all the numbers together, and all the variables

2e-(3e-12)=0

We get rid of parentheses

2e-3e+12=0

We add all the numbers together, and all the variables

-1e+12=0

We move all terms containing e to the left, all other terms to the right

-e=-12

e=-12/-1

e=+12

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