3(3h+2)-2(h+5)=2(h-5)-4

Solution for 3(3h+2)-2(h+5)=2(h-5)-4 equation:

3(3h+2)-2(h+5)=2(h-5)-4

We move all terms to the left:

3(3h+2)-2(h+5)-(2(h-5)-4)=0

We multiply parentheses

9h-2h-(2(h-5)-4)+6-10=0


We calculate terms in parentheses: -(2(h-5)-4), so:

2(h-5)-4

We multiply parentheses

2h-10-4

We add all the numbers together, and all the variables

2h-14

Back to the equation:

-(2h-14)


We add all the numbers together, and all the variables

7h-(2h-14)-4=0

We get rid of parentheses

7h-2h+14-4=0

We add all the numbers together, and all the variables

5h+10=0

We move all terms containing h to the left, all other terms to the right

5h=-10

h=-10/5

h=-2