3(3i-3)=27

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Solution for 3(3i-3)=27 equation: 



3(3i-3)=27

We move all terms to the left:

3(3i-3)-(27)=0

We multiply parentheses

9i-9-27=0

We add all the numbers together, and all the variables

9i-36=0

We move all terms containing i to the left, all other terms to the right

9i=36

i=36/9

i=4

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