3(3j-2)=2(4j+3)

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Solution for 3(3j-2)=2(4j+3) equation: 



3(3j-2)=2(4j+3)

We move all terms to the left:

3(3j-2)-(2(4j+3))=0

We multiply parentheses

9j-(2(4j+3))-6=0



We calculate terms in parentheses: -(2(4j+3)), so:

2(4j+3)

We multiply parentheses

8j+6

Back to the equation:

-(8j+6)



We get rid of parentheses

9j-8j-6-6=0

We add all the numbers together, and all the variables

j-12=0

We move all terms containing j to the left, all other terms to the right

j=12

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