3(3k+2)+7=4(2k+3)+k+1

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Solution for 3(3k+2)+7=4(2k+3)+k+1 equation: 


Simplifying
3(3k + 2) + 7 = 4(2k + 3) + k + 1

Reorder the terms:
3(2 + 3k) + 7 = 4(2k + 3) + k + 1
(2 * 3 + 3k * 3) + 7 = 4(2k + 3) + k + 1
(6 + 9k) + 7 = 4(2k + 3) + k + 1

Reorder the terms:
6 + 7 + 9k = 4(2k + 3) + k + 1

Combine like terms: 6 + 7 = 13
13 + 9k = 4(2k + 3) + k + 1

Reorder the terms:
13 + 9k = 4(3 + 2k) + k + 1
13 + 9k = (3 * 4 + 2k * 4) + k + 1
13 + 9k = (12 + 8k) + k + 1

Reorder the terms:
13 + 9k = 12 + 1 + 8k + k

Combine like terms: 12 + 1 = 13
13 + 9k = 13 + 8k + k

Combine like terms: 8k + k = 9k
13 + 9k = 13 + 9k

Add '-13' to each side of the equation.
13 + -13 + 9k = 13 + -13 + 9k

Combine like terms: 13 + -13 = 0
0 + 9k = 13 + -13 + 9k
9k = 13 + -13 + 9k

Combine like terms: 13 + -13 = 0
9k = 0 + 9k
9k = 9k

Add '-9k' to each side of the equation.
9k + -9k = 9k + -9k

Combine like terms: 9k + -9k = 0
0 = 9k + -9k

Combine like terms: 9k + -9k = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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