3(3k+5)+4k=-6(-2k-1)-2

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Solution for 3(3k+5)+4k=-6(-2k-1)-2 equation: 



3(3k+5)+4k=-6(-2k-1)-2

We move all terms to the left:

3(3k+5)+4k-(-6(-2k-1)-2)=0

We add all the numbers together, and all the variables

4k+3(3k+5)-(-6(-2k-1)-2)=0

We multiply parentheses

4k+9k-(-6(-2k-1)-2)+15=0



We calculate terms in parentheses: -(-6(-2k-1)-2), so:

-6(-2k-1)-2

We multiply parentheses

12k+6-2

We add all the numbers together, and all the variables

12k+4

Back to the equation:

-(12k+4)



We add all the numbers together, and all the variables

13k-(12k+4)+15=0

We get rid of parentheses

13k-12k-4+15=0

We add all the numbers together, and all the variables

k+11=0

We move all terms containing k to the left, all other terms to the right

k=-11

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