3(3k-10)+1=8(3/2k+3)

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Solution for 3(3k-10)+1=8(3/2k+3) equation: 



3(3k-10)+1=8(3/2k+3)

We move all terms to the left:

3(3k-10)+1-(8(3/2k+3))=0



Domain of the equation: 2k+3))!=0

k∈R



We multiply parentheses

9k-(8(3/2k+3))-30+1=0

We multiply all the terms by the denominator


9k*2k-30*2k+3))+1*2k+3))+3))-(8(3=0

Wy multiply elements

18k^2-60k+3))+1*2k+3))+3))-(8(3=0

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