3(3k-10)-7=k+35

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Solution for 3(3k-10)-7=k+35 equation: 



3(3k-10)-7=k+35

We move all terms to the left:

3(3k-10)-7-(k+35)=0

We multiply parentheses

9k-(k+35)-30-7=0

We get rid of parentheses

9k-k-35-30-7=0

We add all the numbers together, and all the variables

8k-72=0

We move all terms containing k to the left, all other terms to the right

8k=72

k=72/8

k=9

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