3(3k-13)+3(k+5)=48

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Solution for 3(3k-13)+3(k+5)=48 equation:



3(3k-13)+3(k+5)=48
We move all terms to the left:
3(3k-13)+3(k+5)-(48)=0
We multiply parentheses
9k+3k-39+15-48=0
We add all the numbers together, and all the variables
12k-72=0
We move all terms containing k to the left, all other terms to the right
12k=72
k=72/12
k=6

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