3(3k-13)+3(k+5)=48

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Solution for 3(3k-13)+3(k+5)=48 equation: 



3(3k-13)+3(k+5)=48

We move all terms to the left:

3(3k-13)+3(k+5)-(48)=0

We multiply parentheses

9k+3k-39+15-48=0

We add all the numbers together, and all the variables

12k-72=0

We move all terms containing k to the left, all other terms to the right

12k=72

k=72/12

k=6

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