3(3k-3)=-36

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Solution for 3(3k-3)=-36 equation: 



3(3k-3)=-36

We move all terms to the left:

3(3k-3)-(-36)=0

We add all the numbers together, and all the variables

3(3k-3)+36=0

We multiply parentheses

9k-9+36=0

We add all the numbers together, and all the variables

9k+27=0

We move all terms containing k to the left, all other terms to the right

9k=-27

k=-27/9

k=-3

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