3(3k-6)-5=4(k+4)+1

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Solution for 3(3k-6)-5=4(k+4)+1 equation: 



3(3k-6)-5=4(k+4)+1

We move all terms to the left:

3(3k-6)-5-(4(k+4)+1)=0

We multiply parentheses

9k-(4(k+4)+1)-18-5=0



We calculate terms in parentheses: -(4(k+4)+1), so:

4(k+4)+1

We multiply parentheses

4k+16+1

We add all the numbers together, and all the variables

4k+17

Back to the equation:

-(4k+17)



We add all the numbers together, and all the variables

9k-(4k+17)-23=0

We get rid of parentheses

9k-4k-17-23=0

We add all the numbers together, and all the variables

5k-40=0

We move all terms containing k to the left, all other terms to the right

5k=40

k=40/5

k=8

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