3(3k-7)-4(4k+2)=5-2(k+2

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Solution for 3(3k-7)-4(4k+2)=5-2(k+2 equation: 



3(3k-7)-4(4k+2)=5-2(k+2

We move all terms to the left:

3(3k-7)-4(4k+2)-(5-2(k+2)=0

We multiply parentheses

9k-16k-(5-2(k+2)-21-8=0

We add all the numbers together, and all the variables

-7k-(5-2(k+2)-21-8=0

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