3(3k-7)-4(4k+2)=5-2(k+2

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Solution for 3(3k-7)-4(4k+2)=5-2(k+2 equation:



3(3k-7)-4(4k+2)=5-2(k+2
We move all terms to the left:
3(3k-7)-4(4k+2)-(5-2(k+2)=0
We multiply parentheses
9k-16k-(5-2(k+2)-21-8=0
We add all the numbers together, and all the variables
-7k-(5-2(k+2)-21-8=0

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